# How to test the rechargeable battery pack test?

## Method for detecting capacity of rechargeable battery

For example, a 1500mAh rechargeable battery is fully charged. The discharge current of 1500mA can reach 1 hour to prove that the capacity is sufficient. If a 750mA rechargeable battery is used, discharge it for 2 hours for capacity testing. But when the voltage is 0.9Volt (1.2Volt rechargeable battery), there is still a nominal current discharge, how to understand.

Battery capacity refers to the use capacity of the battery. Therefore, when the 1500mAh rechargeable battery is discharged from 1.45Volt to 0.9Volt, the capacity we need is the capacity we need. We don’t use the capacity below 0.9Volt, and the discharged power is not much (too low discharge will also Affect the service life of the battery), usually the discharge platform of a high-quality rechargeable battery is more reliable, for example: a 1500mAh battery is discharged from 1.45Volt to 0.9Volt at a current of 0.5C, and it is left for 120 minutes, then we will say that the battery is The actual use capacity is 1500mAh. The relationship between current, voltage and time in 120 minutes is shown in the figure:

On the contrary, when the discharge voltage of the inferior battery is from 1.45Volt to 0.9Volt, the battery voltage drops quickly, and the voltage drops relatively slowly after 0.9Volt, indicating that the battery performance is not good enough, and the capacity is usually very low.
Note: I: the basic unit of current, ampere or milliampere;
F: The unit of the capacity of the reaction capacitor to store charge, [1/hour], when narrating, only \”number\” is often mentioned, not the unit;
C: Battery charge and discharge capacity ratio, namely battery capacity, unit: ampere hour or milliampere hour
For example, when the battery capacity is 1000mAh, it is charged at a current of 0.1C, which is equivalent to clear:
The charging current to the battery I=0.1[1/hour] X1000[mA hour]=100[mA]
F is also called \”charging (discharging) rate in n hours\”, f =1/(n hours)